2[4(x+6+1)+1]+3x=17

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Solution for 2[4(x+6+1)+1]+3x=17 equation:


Simplifying
2[4(x + 6 + 1) + 1] + 3x = 17

Reorder the terms:
2[4(6 + 1 + x) + 1] + 3x = 17

Combine like terms: 6 + 1 = 7
2[4(7 + x) + 1] + 3x = 17
2[(7 * 4 + x * 4) + 1] + 3x = 17
2[(28 + 4x) + 1] + 3x = 17

Reorder the terms:
2[28 + 1 + 4x] + 3x = 17

Combine like terms: 28 + 1 = 29
2[29 + 4x] + 3x = 17
[29 * 2 + 4x * 2] + 3x = 17
[58 + 8x] + 3x = 17

Combine like terms: 8x + 3x = 11x
58 + 11x = 17

Solving
58 + 11x = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-58' to each side of the equation.
58 + -58 + 11x = 17 + -58

Combine like terms: 58 + -58 = 0
0 + 11x = 17 + -58
11x = 17 + -58

Combine like terms: 17 + -58 = -41
11x = -41

Divide each side by '11'.
x = -3.727272727

Simplifying
x = -3.727272727

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